In an isothermal process, the pressure on 1 mol of an ideal monatomic gas suddenly changes from 4.00 atm to 100.0 atm at 25°C.
-Calculate ΔV.

Question

Quizplus · Accepted Answer

According to Boyle's law, PV = constant, for an isothermal process. So, P₁V₁ = P₂V₂, where P₁ and V₁ are the initial pressure and volume, and P₂ and V₂ are the final pressure and volume. Solving for V₂, we get V₂ = (P₁V₁)/P₂. Substituting the given values, we get V₂ = (4.00 atm * V₁)/100.0 atm = 0.04V₁. Therefore, ΔV = V₂ - V₁ = -0.96V₁ = -5.87 L.

In an Isothermal Process, the Pressure on 1 Mol of an Ideal