Which of the following complexes would be diamagnetic (all electrons paired)? A) Fe(CN)₆]^4- B) Mn(CN)₆]^4- C) V(CN)₆]^3- D) [Cr(CN)₆]^3-

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Quizplus · Accepted Answer

In Fe(CN)[SBU16][SBU0][SBU14-][SBU0], Fe has a 3d6 electron configuration, which gives rise to six unpaired electrons. Therefore, Fe(CN)[SBU16][SBU0][SBU14-][SBU0] is paramagnetic. However, CN- is a strong-field ligand, so it causes pairing of the d electrons in Fe2+. Therefore, all electrons are paired, and Fe(CN)[SBU16][SBU0][SBU14-][SBU0] is diamagnetic. Choices B, C, and D all contain transition metals with unpaired d electrons and therefore are all paramagnetic.

Which of the Following Complexes Would Be Diamagnetic (All Electrons