Which of the following is the correct order of boiling points for NaNO₃, C₂H₅OH, C₂H₆, and Ne? A) Ne

Question

Which of the following is the correct order of boiling points for NaNO₃, C₂H₅OH, C₂H₆, and Ne? A) Ne < C₂H₆ < NaNO₃ < C₂H₅OH B) Ne < C₂H₆ < C₂H₅OH < NaNO₃ C) Ne < C₂H₅OH < C₂H₆ < NaNO₃ D) NaNO₃ < C₂H₅OH < C₂H₆ < Ne E) C₂H₆ < Ne < C₂H₅OH < NaNO₃

Quizplus · Accepted Answer

The boiling point increases with increasing molecular weight and intermolecular forces. Ne is a noble gas, so it has weak London dispersion forces and the lowest boiling point. NaNO₃ has the highest molecular weight and multiple polar bonds, giving it the highest boiling point. C₂H₆ has more polar bonds and a higher molecular weight than C₂H₅OH, giving it a higher boiling point. Therefore, the correct order is Ne < C₂H₆ < C₂H₅OH < NaNO₃.

Which of the Following Is the Correct Order of Boiling