An aqueous solution contains 42.4 g of propanol (C₃H₇OH) in 113.6 g of solution. What is the mole fraction of propanol? A) 0.151 B) 0.272 C) 0.217 D) 0.179 E) 0.849

Question

Quizplus · Accepted Answer

The mole fraction of propanol is calculated by dividing the moles of propanol by the total moles of solution. The moles of propanol are calculated by dividing the mass of propanol by its molar mass (60.1 g/mol). The total moles of solution are calculated by dividing the mass of solution by the molar mass of water (18.0 g/mol).Moles of propanol = 42.4 g / 60.1 g/mol = 0.705 molMoles of water = 113.6 g / 18.0 g/mol = 6.31 molTotal moles of solution = 0.705 mol + 6.31 mol = 7.02 molMole fraction of propanol = 0.705 mol / 7.02 mol = 0.1005Therefore, the mole fraction of propanol is 0.1005, which is closest to choice A, 0.151.

An Aqueous Solution Contains 42