Calculate the molality of a solution containing 21.0 g of C₆H₁₂O₆ in 271.0 mL of water (assume a density of 1.00 g/mL). A) 0.399 m B) 0.0719 m C) 0.000430 m D) 0.430 m E) 0.00768 m

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Quizplus · Accepted Answer

Molality (m) is calculated as moles of solute per kilogram of solvent. First, calculate moles of C6H12O6: 21.0 g / 180.18 g/mol = 0.1165 mol. The mass of water is 271.0 g (since density is 1.00 g/mL). Convert to kg: 271.0 g = 0.271 kg. Molality = 0.1165 mol / 0.271 kg = 0.430 m.

Calculate the Molality of a Solution Containing 21