In peas, axial (A)flower position is dominant to terminal (a), tall (L)is dominant to short (l), and yellow (Y)is dominant to green (y). If a plant that is heterozygous for all three traits is allowed to self-fertilize, how many of the offspring would show the dominant phenotype for all three traits?
A)3/64
B)9/64
C)27/64
D)32/64
E)64/64

Question

Quizplus · Accepted Answer

When a heterozygous plant (AaLlYy) self-fertilizes, the probability of showing the dominant phenotype for each trait is 3/4. Therefore, the probability for all three traits is (3/4) * (3/4) * (3/4) = 27/64.

In Peas, Axial (A)flower Position Is Dominant to Terminal (A)