If an X-linked recessive trait has a frequency of 5% in males, what percentage of females are carriers? (Assume that the population is in Hardy-Weinberg equilibrium.)
A)9.5%
B)5%
C)95%
D)4.2%
E)10%

Question

Quizplus · Accepted Answer

The frequency of the recessive allele in males is 0.05, so the frequency of the dominant allele is 0.95. The frequency of heterozygous females is 2pq, where p is the frequency of the dominant allele and q is the frequency of the recessive allele. Therefore, the frequency of heterozygous females is 2(0.95)(0.05) = 0.095, or 9.5%.

If an X-Linked Recessive Trait Has a Frequency of 5