What is the freezing point for a solution containing 1.00 mole of NaCl (an ionic component) dissolved in 1.00 kg of water? A) +1.86^oC B) -1.86^oC C) +3.72^oC D) -3.72^oC

Question

Quizplus · Accepted Answer

The freezing point depression of a solution is calculated using the formula ΔTf = iKf m, where ΔTf is the change in freezing point, i is the van't Hoff factor (which is 2 for NaCl, as it dissociates into two ions: Na+ and Cl-), Kf is the freezing point depression constant for water (1.86°C kg/mol), and m is the molality of the solution. For 1.00 mole of NaCl in 1.00 kg of water, the freezing point depression is 2 * 1.86°C = 3.72°C. Since this is a depression, the freezing point is lowered, making the correct answer -3.72°C.

What Is the Freezing Point for a Solution Containing 1