1.00 oz of gold (density = 19.3 g/mL) can be hammered into a sheet that would cover a 1.00 x 10² ft2 area. How thick would such a sheet be in centimeters? A) 1.58 × 10^-5 cm B) 4.82 × 10^-4 cm C) 4.02 × 10^-5 cm D) 6.33 × 10⁴ cm E) 2.11 × 10^-5 cm

Question

Quizplus · Accepted Answer

The correct answer is A because:The volume of gold is:V = m/d = (1.00 oz)(28.35 g/oz)/(19.3 g/mL) = 1.46 mLThe area of the sheet is:A = 1.00 x 10^2 ft^2 = 9.29 x 10^4 cm^2The thickness of the sheet is:t = V/A = (1.46 mL)(1 cm^3/mL)/(9.29 x 10^4 cm^2) = 1.58 x 10^-5 cm

100 Oz of Gold (Density = 19