A lead cube that is 3.00 cm on each side contains 8.91 × 10²³atoms. What is the density of this cube in g/cm3? A) 34.1 B) 11.4 C) 0.0550 D) 0.990 E) 26.7

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Quizplus · Accepted Answer

The density of the cube can be calculated using the formula: Density = Mass/Volume. The volume of the cube is 3.00 cm * 3.00 cm * 3.00 cm = 27.0 cm³. The number of atoms and the atomic mass of lead (207.2 g/mol) can be used to find the mass. Using Avogadro's number (6.022 × 10²³ atoms/mol), the mass is approximately 307.8 g. Thus, the density is 307.8 g / 27.0 cm³ = 11.4 g/cm³.

A Lead Cube That Is 3