If the density of lead is 11.34 g/cm3, how many atoms are in a piece of lead that is 2.00 cm wide, 1.00 m long, and 2.00 mm thick? A) 1.32 × 10²⁴ atoms B) 1.16 × 10²³ atoms C) 1.32 × 10²³ atoms D) 1.16 × 10²² atoms E) 6.60 × 10²³ atoms

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Quizplus · Accepted Answer

The correct answer is A because the density of lead is 11.34 g/cm3, so the mass of the piece of lead is 2.00 cm * 1.00 m * 2.00 mm * 11.34 g/cm3 = 494.96 g. The molar mass of lead is 207.2 g/mol, so the number of moles of lead in the piece is 494.96 g / 207.2 g/mol = 2.39 mol. The number of atoms in the piece is 2.39 mol * 6.022 * 10^23 atoms/mol = 1.44 * 10^24 atoms.

If the Density of Lead Is 11