When the following equation is completed and balanced for the reaction in acidic solution, what is the proper coefficient for H⁺? Zn(s) + Cr₂O₇^2- (aq) → Zn²⁺ (aq) + Cr²⁺ (aq) A) 22 B) 18 C) 14 D) 11 E) 7

Question

Quizplus · Accepted Answer

Starting with the unbalanced equation:

Zn + Cr(S1U1B12S1U1B0O)2 + HS1U1P1+S1S1P0 → ZnS1U1P12 + CrS1U1P12 + H2S

To balance this equation, we can follow these steps:

1. Balance the elements other than hydrogen and oxygen:
Zn + Cr(S1U1B12S1U1B0O)2 + HS1U1P1+S1S1P0 → ZnS1U1P12 + CrS1U1P12 + H2S

2. Balance the oxygen atoms by adding water molecules:
Zn + Cr(S1U1B12S1U1B0O)2 + HS1U1P1+S1S1P0 → ZnS1U1P12 + CrS1U1P12 + H2O + S1S1P0

3. Balance the hydrogen atoms by adding protons (H+):
Zn + Cr(S1U1B12S1U1B0O)2 + HS1U1P1+S1S1P0 → ZnS1U1P12 + CrS1U1P12 + H2O + H+ + S1S1P0

4. Balance the charge by adding electrons:
Zn + Cr(S1U1B12S1U1B0O)2 + HS1U1P1+S1S1P0 → ZnS1U1P12 + CrS1U1P12 + H2O + H+ + S1S1P0 + e-

Now we can see that there are 14 H on the left side and 14 H on the right side. Similarly, there are 14 S atoms on the left side and 14 S atoms on the right side. Therefore, the coefficient of HS1U1P1+S1S1P0 is 14.

Final balanced equation:
Zn + Cr(S1U1B12S1U1B0O)2 + 14HS1U1P1+14S1S1P0 → ZnS1U1P12 + CrS1U1P12 + 7H2O + 14H+ + 14S1S1P0 + 14e-

When the Following Equation Is Completed and Balanced for the Reaction