What is the osmotic pressure in mmHg of 6.00 L of a 0.108 M solution at 30°C if three moles of ions are produced in aqueous solution for every mole of solute dissolved? A) 8.05 mmHg B) 3.68 × 10⁴ mmHg C) 2.04 × 10³ mmHg D) 0.0613 mmHg E) 6.13 × 10³ mmHg

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Quizplus · Accepted Answer

The osmotic pressure (π) can be calculated using the formula π = iMRT, where i is the van't Hoff factor (3 in this case), M is the molarity (0.108 M), R is the ideal gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin (303 K). Calculating gives π = 3 × 0.108 × 0.0821 × 303 = 6.13 × 10³ mmHg.

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