What is the pH of a 0.563 M solution of ethylammonium bromide? Kb (ethylammonia) = 4.3 × 10^-4 A) 8.58 B) 1.79 C) 8.68 D) 5.32 E) 5.44

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Ethylammonium bromide is a salt of a weak base (ethylamine) and a strong acid (HBr). The pH can be calculated using the formula for the hydrolysis of the cation: pH = 7 - 0.5(pKa + log C), where pKa = 14 - pKb. Substituting the given values, we find the pH to be approximately 5.44.

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