A certain acid, HA, has a Ka given by: HA + H2O ⇌ H3O+ + A- Ka = 6.80 × 10-6
What is the pH of a 0.247 M solution of the acid's potassium salt, KA, which undergoes the hydrolysis reaction?
A- + H2O ⇌ OH- + HA
A) 4.72
B) 9.28
C) 4.11
D) 9.89
E) 9.44
Correct Answer:
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