What is the concentration of free sulfate ion in a solution labeled "3.6M H₂SO₄"? [Ka2 = 1.1 × 10^-2] A) 0.011 M B) 0.040 M C) 0.20 M D) 0.60 M E) 1.8 M

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Quizplus · Accepted Answer

The correct answer is A because the concentration of free sulfate ion in a solution labeled "3.6M H₂SO₄" can be calculated using the dissociation constant Ka2 for the second dissociation of sulfuric acid. The Ka2 value is 1.1 × 10^-2, which means that the equilibrium constant for the reaction HSO₄^- + H₂O <=> H₃O⁺ + SO₄^2- is 1.1 × 10^-2. This means that the concentration of free sulfate ion in the solution will be 1.1 × 10^-2 M.

What Is the Concentration of Free Sulfate Ion in a Solution