A 0.214 M solution of a monoprotic base has a pH of 11.48. What is the ionization constant of this base? A) 1.4 × 10^-2 B) 4.3 × 10^-5 C) 1.5 × 10^-11 D) 5.1 × 10^-23 E) 2.0 × 10^-6

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Quizplus · Accepted Answer

The pH of 11.48 corresponds to a pOH of 2.52, indicating an OH⁻ concentration of 3.02 × 10⁻³ M. Using the formula Kb = [OH⁻]² / [Base], we find Kb = (3.02 × 10⁻³)² / 0.214 = 4.3 × 10⁻⁵.

A 0214 M Solution of a Monoprotic Base Has a PH