What volume in ml of 0.05 M NaOH would have to be added to 50.0 ml of 0.10 M H₂SO₄ in order to affect complete neutralization of the acid? A) 50 mL B) 20 mL C) 100 mL D) 150 mL E) 200 mL

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H₂SO₄ is a diprotic acid, meaning it can donate two protons. The reaction is: H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O. Therefore, 1 mole of H₂SO₄ reacts with 2 moles of NaOH. The moles of H₂SO₄ in 50 mL of 0.10 M solution is 0.005 moles. Thus, 0.01 moles of NaOH are needed. Using the formula Molarity = moles/volume, the volume of 0.05 M NaOH needed is 0.01 moles / 0.05 M = 0.2 L or 200 mL.

What Volume in Ml of 0