Consider the following reaction:
4 NH₃(g) + 7 O₂(g) → 4 NO₂(g) + 6 H₂O (l) ΔG°f -16.7 0.0 51.8 -237.2 kJ/mol
What is Keq for this reaction at 25 °C?

Question

Quizplus · Accepted Answer

The equilibrium constant (Keq) can be calculated using the Gibbs free energy change (ΔG°) and the temperature (T) using the equation:Keq = e^(-ΔG°/RT)where R is the ideal gas constant (8.314 J/mol·K).At 25 °C (298 K), the equilibrium constant for the given reaction is:Keq = e^(-(-16.7 kJ/mol)/(8.314 J/mol·K * 298 K)) = e^(464)Therefore, the correct answer is B) e^464.

Consider the Following Reaction