For Cl₂O(g) + 3/2 O₂(g) → 2 ClO₂ △H° = 126 kJ/mol, and ΔS° = -74.9 J/(mol∙deg) at 377°C. What is Keq? A) 0.97 B) 6.12 × 10^-7 C) 4.27 × 10^-22 D) 9.17 × 10^-15 E) 1.07 × 10¹⁴

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Quizplus · Accepted Answer

The Gibbs free energy change (ΔG°) can be calculated using ΔG° = ΔH° - TΔS°. At 377°C (650K), ΔG° = 126,000 J/mol - 650K * (-74.9 J/(mol∙K)) = 174,185 J/mol. Keq is calculated using ΔG° = -RTln(Keq), leading to Keq = e^(-ΔG°/RT). Solving gives Keq ≈ 9.17 × 10^-15.

For Cl2O(g) + 3/2 O2(g) → 2 ClO2 &Emsp; &Emsp;

For Cl₂O(g) + 3/2 O₂(g) → 2 ClO₂ &Emsp; &Emsp;