Calculate the number of grams of aluminum produced in the electrolytic process when 2.5 × 10⁵ coulombs are provided to the reaction. Assume 100% efficiency. A) 23 g B) 7.7 g C) 70 g D) 3.5 g E) 11 g

Question

Quizplus · Accepted Answer

The number of moles of electrons transferred is:2.5 × 10⁵ C / (1.602 × 10^-19 C/mol) = 156.1 molThe balanced equation for the electrolysis of aluminum is:2Al³⁺ + 6e^- → 2AlSo, 156.1 mol of electrons will produce 156.1/3 mol of aluminum.The molar mass of aluminum is 26.98 g/mol.So, the mass of aluminum produced is:(156.1/3 mol) × (26.98 g/mol) = 1420 g = 1.42 kg

Calculate the Number of Grams of Aluminum Produced in the Electrolytic