An analysis of a Solvay plant show that for every 4.30 tons of NaCl consumed, 4.75 tons of NaHCO₃ is obtained. What is the % efficiency of this process for converting NaCl to NaHCO₃? A) 76.8% B) 61.8% C) 63.0% D) 158% E) 90.5%

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Quizplus · Accepted Answer

The % efficiency of the process is given by:% efficiency = (Actual yield / Theoretical yield) x 100The theoretical yield of NaHCO3 is:4.30 tons NaCl x (4.75 tons NaHCO3 / 4.30 tons NaCl) = 4.75 tons NaHCO3The % efficiency is:% efficiency = (4.75 tons NaHCO3 / 4.75 tons NaHCO3) x 100 = 100%Therefore, the % efficiency of the process is 100%.

An Analysis of a Solvay Plant Show That for Every