Consider a locus with two alleles, A and A) If the rate of mutation of A to a is 0.0000025 and the rate of mutation of a to A is 0.0000010, what will be the equilibrium frequency of the A allele? (Recall that the equilibrium allele frequency under mutation is p*= v+$\mu$( v), where p*is the equilibrium frequency of the A allele, $\mu$ is the rate of mutation from A to a, and v is the rate of mutation from a to
A) 0.0407
B) 0.1298
C) 0.2857
D) 0.3869

Question

Consider a locus with two alleles, A and A) If the rate of mutation of A to a is 0.0000025  and the rate of mutation of a to A is 0.0000010, what will be the equilibrium frequency of the A allele? (Recall that the equilibrium allele frequency under mutation is p*= v+$\mu$( v), where p*is the equilibrium frequency of the A allele, $\mu$ is the rate of mutation from A to a, and v is the rate of mutation from a to
A) 0.0407
B) 0.1298
C) 0.2857
D) 0.3869

Quizplus · Accepted Answer

The equilibrium frequency of the A allele (p*) can be calculated using the formula p* = v / (μ + v), where μ is the mutation rate from A to a, and v is the mutation rate from a to A. Plugging in the given values, p* = 0.0000010 / (0.0000025 + 0.0000010) = 0.0000010 / 0.0000035 = 0.2857.

Consider a Locus with Two Alleles, a and A) If μ\muμ

Consider a Locus with Two Alleles, a and A) If $\mu$