A repeated-measures study comparing two treatments with a sample of n = 4 participants produces M_D = 3 with SS = 48 for the set of difference scores.What is the repeated-measures t statistic for these data? A)3/3 = 1.73 B)3/2 = 1.50 C)3/4 = 0.75 D)3/16 = 0.19

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Quizplus · Accepted Answer

The repeated-measures t statistic is calculated as: t = Mdiff / (SDdiff / sqrt(n)) Where Mdiff is the mean of the difference scores, SDdiff is the standard deviation of the difference scores, and n is the sample size. We are given SS = 48, which can be used to calculate the variance of the difference scores: variance = SS / (n-1) = 48 / (4-1) = 16 We can then calculate the standard deviation of the difference scores: SDdiff = sqrt(variance) = sqrt(16) = 4 We are also given M_D = 3, which is the mean of the difference scores. Therefore: Mdiff = 3 Plugging in these values, we get: t = Mdiff / (SDdiff / sqrt(n)) = 3 / (4 / sqrt(4)) = 3/2 Therefore, the repeated-measures t statistic for these data is 1.50, which corresponds to choice B.

A Repeated-Measures Study Comparing Two Treatments with a Sample of N