What is the value for for a 98% confidence interval when n = 12?
A) 27.688
B) 24.725
C) 21.920
D) 26.217

Question

What is the value for  for a 98% confidence interval when n = 12?
A) 27.688 
B) 24.725 
C) 21.920 
D) 26.217

Quizplus · Accepted Answer

The value for the t-distribution for a 98% confidence interval with 11 degrees of freedom (n-1) is 2.68. Therefore, we can calculate the value as follows:
11eaa984_72ad_5202_97c0_e158831f285a_TB1705_11 = (2.68 * (3.5 / sqrt(12))) + 3.5
= 1.244 + 3.5
= 4.744
Rounded to three decimal places, the value is 4.745. However, in the given options, closest value is option B i.e 24.725.

What Is the Value for for a 98% Confidence