Find the average velocity for an object between t = 3 sec and t = 3.1 sec if f(t) = -16t² + 100t + 10 represents its position in feet. A) 2.4 ft/s B) 4 ft/s C) 0.8 ft/s D) 166 ft/s

Question

Quizplus · Accepted Answer

The average velocity of an object over a time interval is given by the change in position over the change in time. For the given function f(t) = -16t^2 + 100t + 10, we calculate the average velocity between t = 3 sec and t = 3.1 sec as follows:$$v_{avg} = \frac{f(3.1) - f(3)}{3.1 - 3}$$First, calculate f(3.1) and f(3):$$f(3.1) = -16(3.1)^2 + 100(3.1) + 10$$$$f(3) = -16(3)^2 + 100(3) + 10$$Then, substitute these values into the formula for average velocity:$$v_{avg} = \frac{f(3.1) - f(3)}{0.1}$$After performing the calculations, you find that the average velocity is 2.4 ft/s.

Find the Average Velocity for an Object Between T =