The text describes logistic growth with an equation for the actual population in terms of a growth constant and a maximum population (carrying capacity), . The equation could also be written for a fraction of the maximum population in terms of a fractional growth constant. Re-express the differential equation in terms of the fractional population, . Compare the time it takes for the population to go from 60% of the maximum to 80% of the maximum with the time it takes to go from 80% of the maximum to 90% of the maximum, if k = 0.00100 day^-1 and M = 4000?

Question

Quizplus · Accepted Answer

The Answer of The text describes logistic growth with an equation for the actual population in terms of a growth constant and a maximum population (carrying capacity), . The equation could also be written for a fraction of the maximum population in terms of a fractional growth constant. Re-express the differential equation in terms of the fractional population, . Compare the time it takes for the population to go from 60% of the maximum to 80% of the maximum with the time it takes to go from 80% of the maximum to 90% of the maximum, if k = 0.00100 day^-1 and M = 4000?

The Text Describes Logistic Growth with an Equation for the Actual