The freezing point of a 0.0925 m solution of ammonium chloride was found to be -0.325 $\circ$ C. What is the actual van't Hoff factor for this salt at this concentration compared to the ideal one of 2? K_f(water) = 1.86 $\circ$ C/m A)1.89 B)1.95 C)1.90 D)1.80 E)1.97

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The Answer of The freezing point of a 0.0925 m solution of ammonium chloride was found to be -0.325 $\circ$ C. What is the actual van't Hoff factor for this salt at this concentration compared to the ideal one of 2? K_f(water) = 1.86 $\circ$ C/m A)1.89 B)1.95 C)1.90 D)1.80 E)1.97

The Freezing Point of a 0 ∘\circ∘ C What Is the Actual Van't Hoff Factor for This

The Freezing Point of a 0 $\circ$ C What Is the Actual Van't Hoff Factor for This