Calculate the molality of a solution containing 0.355 mol sodium hydrogen carbonate (baking soda) and 245 g of water. A)1.45 m B)1.12 $\times$ 10^-2 m C)2.11 m D)1.12 $\times$ 10^-3 m E)0.0211 m

Question

Quizplus · Accepted Answer

Molality (m) is calculated using the formula $m = \frac{\text{moles of solute}}{\text{kilograms of solvent}}$. Here, the moles of sodium hydrogen carbonate are 0.355 mol, and the mass of water (solvent) is 245 g, which is 0.245 kg. Thus, $m = \frac{0.355}{0.245} = 1.45 \, \text{m}$.

Calculate the Molality of a Solution Containing 0 ×\times× 10-2 M C)2

Calculate the Molality of a Solution Containing 0 $\times$ 10^-2 M
C)2