Nickel (Ni) crystallizes as a face-centered unit cell with an edge length of 382 pm. What is the atomic radius of nickel?
A)135 pm
B)165 pm
C)191 pm
D)252 pm
E)1,080 pm

Question

Quizplus · Accepted Answer

The atomic radius in a face-centered cubic (FCC) structure can be calculated using the formula $r = \frac{\sqrt{2}a}{4}$, where $a$ is the edge length of the unit cell. For nickel, with an edge length ($a$) of 382 pm, the atomic radius ($r$) is calculated as $r = \frac{\sqrt{2} \times 382 \text{ pm}}{4} = \frac{540.7 \text{ pm}}{4} = 135.175 \text{ pm}$, which rounds to 135 pm.

Nickel (Ni) Crystallizes as a Face-Centered Unit Cell with an Edge