The minimum amount of 100-degree-C steam needed to melt 1 gram of 0-degree-Celsius ice is
A)0)125 gram.
B)0)148 gram.
C)6)75 grams.
D)8 grams.
E)none of these

Question

Quizplus · Accepted Answer

The heat of fusion of ice is 334 J/g, and the specific heat of water is 4.18 J/g-°C. So, the heat required to melt 1 gram of ice is 334 J, and the heat required to raise the temperature of the resulting water from 0°C to 100°C is 100 J. Therefore, the total heat required is 434 J. Since the heat of condensation of steam is 2260 J/g, the minimum amount of steam needed is 434 J / 2260 J/g = 0.192 g.

The Minimum Amount of 100-Degree-C Steam Needed to Melt 1