Let $z = \ln \sqrt { x ^ { 2 } + y ^ { 2 } }$ , $x = r \cos \theta$ , and $y = r \sin \theta$ . Use the chain rule to find $\frac { \delta z } { \delta r }$ and $\frac { d z } { \delta \theta }$ .

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The Answer of Let $z = \ln \sqrt { x ^ { 2 } + y ^ { 2 } }$ , $x = r \cos \theta$ , and $y = r \sin \theta$ . Use the chain rule to find $\frac { \delta z } { \delta r }$ and $\frac { d z } { \delta \theta }$ .

Let z=ln⁡x2+y2z = \ln \sqrt { x ^ { 2 } + y ^ { 2 } }z=lnx2+y2​

Let $z = \ln \sqrt { x ^ { 2 } + y ^ { 2 } }$