Find the area of the portion of the surface $z = x ^ { 2 } + y ^ { 2 }$ inside the cylinder $x ^ { 2 } + y ^ { 2 } = 4$ .

Name: Find the area of the portion of the surface $z = x ^ { 2 } + y ^ { 2 }$ inside the cylinder $x ^ { 2 } + y ^ { 2 } = 4$ .
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The Answer of Find the area of the portion of the surface $z = x ^ { 2 } + y ^ { 2 }$ inside the cylinder $x ^ { 2 } + y ^ { 2 } = 4$ .

Find the Area of the Portion of the Surface z=x2+y2z = x ^ { 2 } + y ^ { 2 }z=x2+y2

Find the Area of the Portion of the Surface $z = x ^ { 2 } + y ^ { 2 }$