Find the area of the part of the surface $z = x + y ^ { 2 }$ that lies above the triangle with vertices (0, 0), (1, 1), and (0, 1).

Name: Find the area of the part of the surface $z = x + y ^ { 2 }$ that lies above the triangle with vertices (0, 0), (1, 1), and (0, 1).
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The Answer of Find the area of the part of the surface $z = x + y ^ { 2 }$ that lies above the triangle with vertices (0, 0), (1, 1), and (0, 1).

Find the Area of the Part of the Surface z=x+y2z = x + y ^ { 2 }z=x+y2

Find the Area of the Part of the Surface $z = x + y ^ { 2 }$