At what value(s) of x does the function $\frac { ( x + 1 ) ^ { 2 } } { x ^ { 2 } - 1 }$ have a removable discontinuity?
A)-3
B)3
C)2
D)-1
E)1
F)-4
G)-2
H)4

Question

Quizplus · Accepted Answer

The function has a removable discontinuity at x = -1 because the numerator and denominator both become zero at x = -1, indicating a hole in the graph at this point. Simplifying the function would eliminate this point of discontinuity, hence it's removable.

At What Value(s) of X Does the Function (x+1)2x2−1\frac { ( x + 1 ) ^ { 2 } } { x ^ { 2 } - 1 }x2−1(x+1)2​

At What Value(s) of X Does the Function $\frac { ( x + 1 ) ^ { 2 } } { x ^ { 2 } - 1 }$