Given $f ( x ) = \frac { x - 4 } { x - 1 }$ , find an equation of the line(s) tangent to the graph of $y = f ( x )$ and parallel to $y - 3 x + 7 = 0$ .

Name: Given $f ( x ) = \frac { x - 4 } { x - 1 }$ , find an equation of the line(s) tangent to the graph of $y = f ( x )$ and parallel to $y - 3 x + 7 = 0$ .
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The Answer of Given $f ( x ) = \frac { x - 4 } { x - 1 }$ , find an equation of the line(s) tangent to the graph of $y = f ( x )$ and parallel to $y - 3 x + 7 = 0$ .

Given f(x)=x−4x−1f ( x ) = \frac { x - 4 } { x - 1 }f(x)=x−1x−4​

Given $f ( x ) = \frac { x - 4 } { x - 1 }$