Let $p ( t ) = \frac { 20,000 } { 1 + 1999 e ^ { - 0.1 t } }$ be the population of a bacteria colony at time t hours. Find the growth rate of the bacteria after 10 hours.

Question

Quizplus · Accepted Answer

The Answer of Let $p ( t ) = \frac { 20,000 } { 1 + 1999 e ^ { - 0.1 t } }$ be the population of a bacteria colony at time t hours. Find the growth rate of the bacteria after 10 hours.

Let p(t)=20,0001+1999e−0.1tp ( t ) = \frac { 20,000 } { 1 + 1999 e ^ { - 0.1 t } }p(t)=1+1999e−0.1t20,000​

Let $p ( t ) = \frac { 20,000 } { 1 + 1999 e ^ { - 0.1 t } }$