Find the derivative of $f ( x ) = \frac { 1 } { ( 1 - 2 x ) ^ { 3 } }$ .
A) $\frac { 6 } { ( 1 - 2 x ) ^ { 4 } }$
B) $- \frac { 6 } { ( 1 - 2 x ) ^ { 4 } }$
C) $\frac { 3 } { ( 1 - 2 x ) ^ { 4 } }$
D) $- \frac { 1 } { 6 ( 1 - 2 x ) ^ { 2 } }$
E) $- \frac { 3 } { ( 1 - 2 x ) ^ { 4 } }$
F) $\frac { 1 } { 3 ( 1 - 2 x ) ^ { 2 } }$
G) $- \frac { 2 } { ( 1 - 2 x ) ^ { 4 } }$
H)None of these

Question

Find the derivative of $f ( x ) = \frac { 1 } { ( 1 - 2 x ) ^ { 3 } }$ .
A) $\frac { 6 } { ( 1 - 2 x ) ^ { 4 } }$ 
B) $- \frac { 6 } { ( 1 - 2 x ) ^ { 4 } }$ 
C) $\frac { 3 } { ( 1 - 2 x ) ^ { 4 } }$ 
D) $- \frac { 1 } { 6 ( 1 - 2 x ) ^ { 2 } }$ 
E) $- \frac { 3 } { ( 1 - 2 x ) ^ { 4 } }$
F) $\frac { 1 } { 3 ( 1 - 2 x ) ^ { 2 } }$
G) $- \frac { 2 } { ( 1 - 2 x ) ^ { 4 } }$
H)None of these

Quizplus · Accepted Answer

The derivative of $f ( x ) = \frac { 1 } { ( 1 - 2 x ) ^ { 3 } }$ is $$f'(x) = \frac { d } { d x } \left[ \frac { 1 } { ( 1 - 2 x ) ^ { 3 } } \right] = - \frac { 3 } { ( 1 - 2 x ) ^ { 4 } } \cdot \frac { d } { d x } [ 1 - 2 x ] = \frac { 6 } { ( 1 - 2 x ) ^ { 4 } }$$

Find the Derivative Of f(x)=1(1−2x)3f ( x ) = \frac { 1 } { ( 1 - 2 x ) ^ { 3 } }f(x)=(1−2x)31​

Find the Derivative Of $f ( x ) = \frac { 1 } { ( 1 - 2 x ) ^ { 3 } }$