The cost of operating a bus between Moose Jaw and Saskatoon is $100 + 5 x$ , where x is the number of passengers. If a ticket costs $20, there will be 10 passengers, while if a ticket costs $15, there will be 20 passengers. Assuming the demand function is linear, what is the maximum profit?

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The Answer of The cost of operating a bus between Moose Jaw and Saskatoon is $100 + 5 x$ , where x is the number of passengers. If a ticket costs $20, there will be 10 passengers, while if a ticket costs $15, there will be 20 passengers. Assuming the demand function is linear, what is the maximum profit?

The Cost of Operating a Bus Between Moose Jaw and Saskatoon