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Question 147
If ∫03f(x) dx=4,∫36f(x) dx=4, and ∫26f(x) dx=5, find the value of ∫02f(x) dx. \int _ { 0 } ^ { 3 } f ( x ) d x = 4 , \int _ { 3 } ^ { 6 } f ( x ) d x = 4 \text {, and } \int _ { 2 } ^ { 6 } f ( x ) d x = 5 \text {, find the value of } \int _ { 0 } ^ { 2 } f ( x ) d x \text {. }∫03f(x) dx=4,∫36f(x) dx=4, and ∫26f(x) dx=5, find the value of ∫02f(x) dx.
A) −3- 3−3 B) 3C) 2D) −1- 1−1 E) 0F) 1G) −2- 2−2 H) Cannot be determined
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