Let $s ( t ) = \int _ { 1 } ^ { t ^ { 2 } - 3 t } ( u + 2 ) e ^ { \sqrt [ 4 ] { u } } d u$ be the position function of a particle. When does the particle stop?

Name: Let $s ( t ) = \int _ { 1 } ^ { t ^ { 2 } - 3 t } ( u + 2 ) e ^ { \sqrt [ 4 ] { u } } d u$ be the position function of a particle. When does the particle stop?
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The Answer of Let $s ( t ) = \int _ { 1 } ^ { t ^ { 2 } - 3 t } ( u + 2 ) e ^ { \sqrt [ 4 ] { u } } d u$ be the position function of a particle. When does the particle stop?

Let s(t)=∫1t2−3t(u+2)eu4dus ( t ) = \int _ { 1 } ^ { t ^ { 2 } - 3 t } ( u + 2 ) e ^ { \sqrt [ 4 ] { u } } d us(t)=∫1t2−3t​(u+2)e4u​du

Let $s ( t ) = \int _ { 1 } ^ { t ^ { 2 } - 3 t } ( u + 2 ) e ^ { \sqrt [ 4 ] { u } } d u$