Find k so that the function $f ( x ) = \left\{ \begin{array} { l l }
\frac { k } { x ( \ln x ) ^ { 3 } } & \text { if } x e \
0 & \text { otherwise }
\end{array} \right.$ can serve as the probability density function of a random variable X.
A) $\frac { 1 } { 3 }$
B) $\frac { 1 } { 6 }$
C) $\frac { 1 } { 2 }$
D)1
E)3
F)6
G)2
H)0

Question

Find k so that the function $f ( x ) = \left\{ \begin{array} { l l } 
\frac { k } { x ( \ln x ) ^ { 3 } } & \text { if } x > e \
0 & \text { otherwise }
\end{array} \right.$ can serve as the probability density function of a random variable X.
A) $\frac { 1 } { 3 }$ 
B) $\frac { 1 } { 6 }$ 
C) $\frac { 1 } { 2 }$ 
D)1
E)3
F)6
G)2
H)0

Quizplus · Accepted Answer

The Answer of Find k so that the function $f ( x ) = \left\{ \begin{array} { l l } 
\frac { k } { x ( \ln x ) ^ { 3 } } & \text { if } x > e \
0 & \text { otherwise }
\end{array} \right.$ can serve as the probability density function of a random variable X.
A) $\frac { 1 } { 3 }$ 
B) $\frac { 1 } { 6 }$ 
C) $\frac { 1 } { 2 }$ 
D)1
E)3
F)6
G)2
H)0

Find K So That the Function f(x)={kx(ln⁡x)3 if x>e0 otherwise f ( x ) = \left\{ \begin{array} { l l } \frac { k } { x ( \ln x ) ^ { 3 } } & \text { if } x > e \\0 & \text { otherwise }\end{array} \right.f(x)={x(lnx)3k​0​ if x>e otherwise ​

Find K So That the Function $f ( x ) = \left\{ \begin{array} { l l } \frac { k } { x ( \ln x ) ^ { 3 } } & \text { if } x > e \\0 & \text { otherwise }\end{array} \right.$