Consider the differential equation $\frac { d y } { d t } = \frac { 2 t x + x } { t ^ { 2 } + t }$ .(a) Find the general solution to the differential equation.(b) Find the solution that satisfies the initial condition $x ( 1 ) = 2$ .

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The Answer of Consider the differential equation $\frac { d y } { d t } = \frac { 2 t x + x } { t ^ { 2 } + t }$ .(a) Find the general solution to the differential equation.(b) Find the solution that satisfies the initial condition $x ( 1 ) = 2$ .

Consider the Differential Equation dydt=2tx+xt2+t\frac { d y } { d t } = \frac { 2 t x + x } { t ^ { 2 } + t }dtdy​=t2+t2tx+x​

Consider the Differential Equation $\frac { d y } { d t } = \frac { 2 t x + x } { t ^ { 2 } + t }$