The heat of combustion of bituminous coal is 2.50 $\times$ 10⁴ J/g.What quantity of the coal is required to produce the energy to convert 106.9 pounds of ice at 0.00°C to steam at 100.°C? specific heat (ice) = 2.10 J/g°C
Specific heat (water) = 4.18 J/g°C
Heat of fusion = 333 J/g
Heat of vaporization = 2258 J/g

Question

The heat of combustion of bituminous coal is 2.50

\times

10⁴ J/g.What quantity of the coal is required to produce the energy to convert 106.9 pounds of ice at 0.00°C to steam at 100.°C? specific heat (ice) = 2.10 J/g°C
Specific heat (water) = 4.18 J/g°C
Heat of fusion = 333 J/g
Heat of vaporization = 2258 J/g

Quizplus · Accepted Answer

The correct answer is A because 5.84 kg of bituminous coal is required to produce the energy to convert 106.9 pounds of ice at 0.00°C to steam at 100.°C.

The Heat of Combustion of Bituminous Coal Is 2 ×\times× 104 J/g

The Heat of Combustion of Bituminous Coal Is 2 $\times$ 10⁴ J/g