What is the boiling point change for a solution containing 0.736 moles of naphthalene (a nonvolatile,nonionizing compound)in 250.g of liquid benzene? (K_b = 2.53°C/m for benzene) A)7.45 °C B)0.859 °C C)3.44 °C D)1.86 °C E)0.466 °C

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Quizplus · Accepted Answer

The boiling point change is given by the equation:ΔT_b = K_b * mwhere K_b is the boiling point elevation constant for the solvent, and m is the molality of the solution.In this case, K_b = 2.53°C/m and m = 0.736 moles / 0.250 kg = 2.94 m.Therefore, ΔT_b = 2.53°C/m * 2.94 m = 7.45 °C.

What Is the Boiling Point Change for a Solution Containing