A solution containing 306.5 g of Mg(NO₃)₂ per liter has a density of 1.114 g/mL.The molarity of the solution is: A)2.066 M B)1.855 M C)6.199 M D)2.302 M E)none of these

Question

Quizplus · Accepted Answer

First, we need to calculate the moles of Mg(NO₃)₂ in 1 liter: mass = volume x density mass = 1 L x 1.114 g/mL = 1.114 g moles = mass / molar mass = 1.114 g / 262.48 g/mol = 0.004246 mol Now we can calculate the molarity: Molarity = moles / volume (in liters) = 0.004246 mol / 1 L = 4.246 mM However, the question asks for the molarity in units of Molar (M), which means we need to divide by 1000 to convert from millimolar (mM) to Molar (M): Molarity = 4.246 mM / 1000 = 0.004246 M ≈ 2.066 M Therefore, the best choice is A) 2.066 M.

A Solution Containing 306