The rate constant for the beta decay of thorium-234 is 2.882 $\times$ 10^-² / day.What is the half-life of this nuclide? A)48.09 days B)1.218 days C)0.693 days D)24.05 days E)96.18 days

Question

Quizplus · Accepted Answer

The half-life (t₁/₂) is calculated using the formula t₁/₂ = 0.693 / k, where k is the rate constant. Substituting the given rate constant, t₁/₂ = 0.693 / 0.02882 ≈ 24.05 days.

The Rate Constant for the Beta Decay of Thorium-234 Is ×\times×

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