The geometry of a coordination compound with a coordination number of 4 is
A) tetrahedral,in order to minimize repulsions between the ligands
B) octahedral,since there are two different positions possible for each ligand
C) square planar,to allow room for the counterion because the ligands take up so much space
D) linear,since there are two ligands on each side of the transition metal
E) tetrahedral or square planar,but too difficult to predict based on the information given
Correct Answer:
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