The Lewis structure for CHCl₃ has nine lone electron pairs.

Question

Quizplus · Accepted Answer

To draw the Lewis structure for CHCl₃, we first need to determine the total number of valence electrons. Carbon (C) has 4 valence electrons, hydrogen (H) has 1 valence electron, chlorine (Cl) has 7 valence electrons, and sulfur (S) has 6 valence electrons. Therefore, the total number of valence electrons in CHCl₃ is: 4 (C) + 1 (H) + 1 (Cl) + 6 (S) + 6 (lone pairs) = 18 When we draw the Lewis structure, we assign 8 electrons to the outer atoms (C, H, Cl), and the remaining 10 electrons are placed as lone pairs on the sulfur atom. Therefore, the Lewis structure for CHCl₃ has 10 lone electron pairs, not 9. The correct answer is Option B.

The Lewis Structure for CHCl3 Has Nine Lone Electron Pairs

The Lewis Structure for CHCl₃ Has Nine Lone Electron Pairs