Consider the following reaction: A₂ + B₂ $\to$ 2AB $\Delta$ H = -365 kJ
The bond energy for A₂ is half the amount of AB.The bond energy of B₂ = 447 kJ/mol.What is the bond energy of A₂?

Question

Consider the following reaction: A₂ + B₂

\to

2AB

\Delta

H = -365 kJ
The bond energy for A₂ is half the amount of AB.The bond energy of B₂ = 447 kJ/mol.What is the bond energy of A₂?

Quizplus · Accepted Answer

The bond energy of A2 is half of AB. Using the reaction enthalpy and bond energies, we can set up the equation: (Bond energy of A2) + (Bond energy of B2) - 2*(Bond energy of AB) = -365 kJ. Solving for the bond energy of A2 gives 271 kJ/mol.

Consider the Following Reaction: A2 + B2 →\to→ 2AB Δ\DeltaΔ H = -365 KJ the Bond Energy for A2 Is

Consider the Following Reaction: A₂ + B₂ $\to$ 2AB $\Delta$ H = -365 KJ
the Bond Energy for A₂ Is